Mole ConceptHard
Question
When burnt in air, a 12.0 g mixture of carbon and sulphur yields a mixture of CO2 and SO2, in which the number of moles of SO2 is half that of CO2. The mass of the carbon the mixture contains is (At. wt. S = 32)
Options
A.4.08 g
B.5.14 g
C.8.74 g
D.1.54 g
Solution
Let mass of C = X gm
C + O2 → CO2
Initial mole
- 0
final mole 0 2a
S + O2 → SO2
Initial mole
- 0
final mole 0 - a
Mole of C = Mole of CO2
= 2a
Mole of S = Mole of SO2
= a
∴
= 2
x =
(12 - x)
4x = 36 - 3x
x =
= 5.14 gm
C + O2 → CO2
Initial mole
- 0 final mole 0 2a
S + O2 → SO2
Initial mole
- 0final mole 0 - a
Mole of C = Mole of CO2
= 2aMole of S = Mole of SO2
= a∴
= 2x =
(12 - x)4x = 36 - 3x
x =
= 5.14 gmCreate a free account to view solution
View Solution FreeMore Mole Concept Questions
Elements P and Q form two types of non-volatile, non-ionizable compounds PQ and ${PQ}_{2}$. When 1 g of PQ is dissolved ...A quantity of 1 g of metallic carbonate XCO3 is completely converted into a chloride XCl2 weighing 1.11 g. The atomic ma...Mole fraction of the component A in vapour phase is x1 and mole fraction of component A in liquid mixture is x2 (PoA = v...The legal limit for human exposure to CO in the work place is 35 ppm. Assuming that the density of air is 1.3 g/L, how m...The empirical formula of compound is CH2O. 0.084 moles of the compound contains 1.0 g of hydrogen. Moleculoar formula of...