JEE AdvancedChemical BondingHard
Question
Which of the following have identical bond order :
Options
A.CN-
B.O2-
C.NO+
D.CN+
Solution
Cn- (14), O2- (17), NO+ (14), CN+ (12)
Cn- : σls2, σ*ls2, σ2s2, σ*2s2,[ π2p2y = π2p2z] σ2p2x
Bond order
O2- : σls2, σ*ls2, σ2s2, σ*2s2, σ2p2x [ π2p2y = π2p2z] [π* 2p2y= π* 2p1z]
Bond order
NO+ : σls2, σ*ls2, σ2s2, σ*2s2, σ2p2x [ π2p2y = π2p2z]
Bond order
CN+ : σls2, σ*ls2, σ2s2, σ*2s2,[ π2p2y = π2p2z] σ2p2x
Bond order
Cn- : σls2, σ*ls2, σ2s2, σ*2s2,[ π2p2y = π2p2z] σ2p2x
Bond order
O2- : σls2, σ*ls2, σ2s2, σ*2s2, σ2p2x [ π2p2y = π2p2z] [π* 2p2y= π* 2p1z]
Bond order
NO+ : σls2, σ*ls2, σ2s2, σ*2s2, σ2p2x [ π2p2y = π2p2z]
Bond order
CN+ : σls2, σ*ls2, σ2s2, σ*2s2,[ π2p2y = π2p2z] σ2p2x
Bond order
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