Question

The electronic configuration of ${H_2}^{2⊝}$ is 
$\Rightarrow \left(\sigma 1s^2\right), \Rightarrow (\sigma *s{)}^2 ,$

Bond order of $H_2^{2⊝}=\frac{N_b-N_a}{2}=\frac{2-2}{2}=0$
Hence $H_2^{2⊝}$does not exist, due to zero bond order.