Chemical BondingMedium
Question
In a closed packed structure of mixed oxides, the lattice is composed of mixed oxides ions. One-eighth of tetrahedral voids are occupied by divalent cations (A2+) while one-half of octahedral voids are occupied by trivalent cations (B3+). The formula of mixed oxide is
Options
A.A2BO3
B.AB2O4
C. A2BO4
D.AB2O4
Solution
For close-packed structure (fcc type)
Number of O2- = 4/unit cell
Number of A2+ =
× TV = 
× 8 = 1
Number of B3+ =
× OV = 
× 4 = 2
Formula: A12+ B23+ O42- ⇒ AB2O4
Number of O2- = 4/unit cell
Number of A2+ =
× TV = × 8 = 1Number of B3+ =
× OV = × 4 = 2Formula: A12+ B23+ O42- ⇒ AB2O4
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