ThermochemistryMedium
Question
ᐃHof of water is - 285.5 kJ mol-1. if enthalpy of neutralisation of monoacid strong base is - 57.3 kJ mol-1, ᐃHof of OH- ion will be
Options
A.- 228.5 kJ mol-1
B.228.5 kJ mol-1
C.114.5 kJ mol-1
D.-114.5 kJ mol-1
Solution
H+(aq) + OH-(aq) → H2O(l)
so ᐃHo = - 57.3 = - 285.5 - ᐃHfo (H+, aq) - ᐃHfo (OH-, aq)
so ᐃHfo (OH-, aq) = - 228.5 kJ/mole (as ᐃHfo (H+, aq) = 0)
so ᐃHo = - 57.3 = - 285.5 - ᐃHfo (H+, aq) - ᐃHfo (OH-, aq)
so ᐃHfo (OH-, aq) = - 228.5 kJ/mole (as ᐃHfo (H+, aq) = 0)
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