Chemical EquilibriumHard
Question
Ammonia dissociates into N2 and H2 such that degree of dissociation a is very less than 1 and equilibrium pressure is P0 then the value of a is [if Kp for 2NH3(g) ⇋ N2 (g) + 3H2(g) is 27 × 10-8 P02:
Options
A.10-4
B.4 × 10-4
C.0.02
D.can′t be calculated.
Solution
2NH3(g) ⇋ N2(g) + 3H2(g) Kp = 
1 - α
1- α ≃ 1 and 1 + α ≃ 1 ⇒ 27 × 10-8 P2o =
Po2 × α4
α = 2 × 10-2
1 - α
1- α ≃ 1 and 1 + α ≃ 1 ⇒ 27 × 10-8 P2o =
Po2 × α4α = 2 × 10-2
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