Atomic StructureHard
Question
The electrons, identified by quantum numbers n and l, (i) n = 4, l = l (ii) n = 4, l = 0 (iii) n = 3, l = 2 and (iv) n = 3, l = 1 can be placed in order of increasing energy from the lowest to highest, as :
Options
A.(iv) < (ii) < ( iii) < (i)
B.(ii) < (iv) < ( i) < (iii)
C.(i) < (iii) < ( ii) < (iv)
D.(iii) < (i) < ( iv) < (ii)
Solution
Using (n + l)
Set : (i) (ii) (iii) (iv)
(n + l) : 5 4 5 4
Thus correct order of increasing energy is
Set : (i) (ii) (iii) (iv)
(n + l) : 5 4 5 4
Thus correct order of increasing energy is
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