SolutionHard
Question
Given at 350 K pAo = 300 torr and pBo = 800 torr, the composition of the mixture having a normal boiling point of 350 K is :
Options
A.XA = 0.08
B.XA = 0.06
C.XA = 0.04
D.XA = 0.02
Solution
760 = 300 XA + 800 (1 - XA)
⇒ 760 = 800 - 500 XA
⇒ 500 XA = 40
∴ XA =
= 0.08.
⇒ 760 = 800 - 500 XA
⇒ 500 XA = 40
∴ XA =
= 0.08.Create a free account to view solution
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