SolutionHard
Question
At 323 K, the vapour pressure in millimeters of mercury of a methanol-ethanol solution is represented by the equation p = 120 XA + 140, where XA is the mole fraction of methanol. Then the value of 
is
isOptions
A.250 mm
B.140 mm
C.260 mm
D.20 mm
Solution
As XA → 1. Then we will have pure methanol so PT = 120 XA + 140 = 120 + 140 = 260 mm of Hg.
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