SolutionHard
Question
A solution of x moles of sucrose in 100 grams of water freezes at -0.2oC. As ice separates the freezing point goes down to 0.25oC. How many grams of ice would have separated?
Options
A.18 grams
B.20 grams
C.25 grams
D.23 grams
Solution
(i) ᐃTf = m × Kf
0.2 =
× 1.86 X = 
after freezing
ᐃTf = m × Kf
ᐃTf =
× 1.86 ᐃTf = 0.25
On solving, Amount of ice y = 20 g ice
0.2 =
× 1.86 X = after freezing
ᐃTf = m × Kf
ᐃTf =
× 1.86 ᐃTf = 0.25On solving, Amount of ice y = 20 g ice
Create a free account to view solution
View Solution FreeMore Solution Questions
In mixture A and B component show - ve deviation as...When concentrated HCl is added to an aqueous solution of CoCl2, its colour changes from reddish pink to deep blue. Which...The vapour pressure of water depends upon :...A semipermeable membrane separates a solution which is 0.012 M in glucose from one that is 0.250 M in glucose. On which ...The depression of freezing points of 0.05 molal aqueous solution of the following compounds are measured.1. NaCl 2. K2SO...