SolutionHard
Question
A solution of x moles of sucrose in 100 grams of water freezes at -0.2oC. As ice separates the freezing point goes down to 0.25oC. How many grams of ice would have separated?
Options
A.18 grams
B.20 grams
C.25 grams
D.23 grams
Solution
(i) ᐃTf = m × Kf
0.2 =
× 1.86 X = 
after freezing
ᐃTf = m × Kf
ᐃTf =
× 1.86 ᐃTf = 0.25
On solving, Amount of ice y = 20 g ice
0.2 =
× 1.86 X = after freezing
ᐃTf = m × Kf
ᐃTf =
× 1.86 ᐃTf = 0.25On solving, Amount of ice y = 20 g ice
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