SolutionHard

Question

Relative decrease in vapour pressure of an aqueous solution containing 2 moles [Cu(NH3)3Cl] Cl in 3 moles H2O is 0.50. On reaction with AgNO3, this solution will form(assuming no change in degree of ionisation of substance on adding AgNO3)

Options

A.1 mol AgCl
B.0.25 mol AgCl
C.0.5 mol AgCl
D.0.40 mol AgCl

Solution


0.5 =
i + 1.5 = 2 i
i = 1.5
i = 1 + (y - 1)α
1.5 = 1 + (2 - 1)α
α = 0.5
mole of Cl- = 1.0
mole of AgCl ppt. = 1.0

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