Coordination CompoundHard
Question
50 ml of 0.2 M solution of a compound with empirical formula CoCl3.4NH3 on treatment with excess of AgNO3(aq) yields 1.435 g of AgCl. Ammonia is not removed by treatment with concentrated H2SO4. The formula of the compound is:
Options
A.Co(NH3)4Cl3
B.[Co(NH3)4Cl2]Cl
C.[Co(NH3)4Cl3
D.[CoCl3(NH3)]NH3
Solution
mole of complex = 50 × 0.2 = 0.01 and mole of AgCl = 
= 0.01
n Ag+ = n Cl-
∴ 1 mole complex = 1 mole AgCl
= 0.01n Ag+ = n Cl-
∴ 1 mole complex = 1 mole AgCl
Create a free account to view solution
View Solution FreeMore Coordination Compound Questions
Which of the following statements is/are correct ?...The only cations present in a slightly acidic solution are Fe3+, Zn2+ and Cu2+. the reagent that when added in excess to...Which of the following complexes has a geometry different from others ?...Which one of the following complexes in an outer orbital complex ?...Co-ordination number of Cr in CrCl3.5H2O is six. The maximum volume of 0.1 N AgNO3 needed to precipitate the chlorine in...