Coordination CompoundHard
Question
50 ml of 0.2 M solution of a compound with empirical formula CoCl3.4NH3 on treatment with excess of AgNO3(aq) yields 1.435 g of AgCl. Ammonia is not removed by treatment with concentrated H2SO4. The formula of the compound is:
Options
A.Co(NH3)4Cl3
B.[Co(NH3)4Cl2]Cl
C.[Co(NH3)4Cl3
D.[CoCl3(NH3)]NH3
Solution
mole of complex = 50 × 0.2 = 0.01 and mole of AgCl = 
= 0.01
n Ag+ = n Cl-
∴ 1 mole complex = 1 mole AgCl
= 0.01n Ag+ = n Cl-
∴ 1 mole complex = 1 mole AgCl
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