Coordination CompoundHard

Question

Match List-I (complex ions) with List-II (number of unpaired electrons) and select the correct answer using the codes given below lists :
        List-I                        List-II
(Complex ions)            (Number of Unpaired Electrons)
A. [CrF6]4-                1. One
B. [MnF6]4-               2. Two
C. [Cr(CN)6]4-          3. Three
D. Mn(CN)6]4-          4. Four
                                  5. Five

Options

A.A → 4
B → 1
C → 2
D → 1
B.A → 2
B → 5
C → 3
D → 1
C.A → 4
B → 5
C → 2
D → 1
D.A → 2
B → 1
C → 3
D → 5

Solution

[CrF6]4-            n = 4    (3d4)
[MnF6]4-           n = 5    (3d5)
[Cr(CN)6]4-      n = 2    (3d4)
[Mn(CN)6]4-     n = 1    (3d5)
n = number of unpaired electrons and that can be calculated by CFT.

Create a free account to view solution

View Solution Free
Topic: Coordination Compound·Practice all Coordination Compound questions

More Coordination Compound Questions

Three arrangements are shown for the complex [Co(en) (NH3)2 Cl2]+. Pick up the wrong statement....The IUPAC name for the complex [Co(NO2)(NH3)5]Cl2 is...On treatment of [Ni(NH3)4]2+ with concentrated HCl, two compounds I and II having the same formula, [NiCl2(NH3)2] are ob...On treatment of [Pt(NH3)4]2+ with concentrated HCl, two compounds (I) and (II) having the same formula, [Pt(NH3)2Cl2] ar...Which of the following complex follow EAN rule ?...