Coordination CompoundHard
Question
Match List-I (complex ions) with List-II (number of unpaired electrons) and select the correct answer using the codes given below lists :
List-I List-II
(Complex ions) (Number of Unpaired Electrons)
A. [CrF6]4- 1. One
B. [MnF6]4- 2. Two
C. [Cr(CN)6]4- 3. Three
D. Mn(CN)6]4- 4. Four
5. Five
List-I List-II
(Complex ions) (Number of Unpaired Electrons)
A. [CrF6]4- 1. One
B. [MnF6]4- 2. Two
C. [Cr(CN)6]4- 3. Three
D. Mn(CN)6]4- 4. Four
5. Five
Options
A.A → 4
B → 1
C → 2
D → 1
B → 1
C → 2
D → 1
B.A → 2
B → 5
C → 3
D → 1
B → 5
C → 3
D → 1
C.A → 4
B → 5
C → 2
D → 1
B → 5
C → 2
D → 1
D.A → 2
B → 1
C → 3
D → 5
B → 1
C → 3
D → 5
Solution
[CrF6]4- n = 4 (3d4)
[MnF6]4- n = 5 (3d5)
[Cr(CN)6]4- n = 2 (3d4)
[Mn(CN)6]4- n = 1 (3d5)
n = number of unpaired electrons and that can be calculated by CFT.
[MnF6]4- n = 5 (3d5)
[Cr(CN)6]4- n = 2 (3d4)
[Mn(CN)6]4- n = 1 (3d5)
n = number of unpaired electrons and that can be calculated by CFT.
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