Coordination CompoundHard
Question
Select the correct statement from the following .
Options
A.[Sc (H2O)6]3+ and [ Ti (H2O)6]3+ both are colourless.
B.Co (NH3)4 Br2Cl show ionization isomers and geometrical isomers.
C.[Pd(NO2)2(NH3)2] is square planar and shows geometrical as well as linkage isomers.
D.Both (B) and (C) are correct.
Solution
(A)Sc3+ - [Ar]18 3d0 4s0 ; there is no unpaired electron in d-orbitals so no d-d transition takes place and the complex is colourless.
Ti3+ - [Ar]18 3d1 4s0 ; It has one unpaired electron; so d-d transition of electron from t2g level to empty level takes place and thus the complex is coloured.
(B) Pd has 4d8 configuration which has higher CFSE and thus the complex is square planar and diamagnetic. In some ligands, like ambidentate ligands, there are two possible coordination sites. In such cases, linkage isomerism exist. e.g.,NO2 group can be bonded to metal ions through nitrogen (-NO2) or through oxygen (-ONO).
Ti3+ - [Ar]18 3d1 4s0 ; It has one unpaired electron; so d-d transition of electron from t2g level to empty level takes place and thus the complex is coloured.
(B) Pd has 4d8 configuration which has higher CFSE and thus the complex is square planar and diamagnetic. In some ligands, like ambidentate ligands, there are two possible coordination sites. In such cases, linkage isomerism exist. e.g.,NO2 group can be bonded to metal ions through nitrogen (-NO2) or through oxygen (-ONO).
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