ElectroMagnetic InductionHard
Question
The given figure represents the phosphor diagram of a series LCR circuit connected to an ac source. At the instant t′ when the source voltage is given by V = V0cosωt; the current in the circuit will be
Options
A.I = I0 cos (ωt′ + π/6)
B.I = I0 cos (ωt′ - π/6)
C.I = I0 cos (ωt′ + π/3)
D.I = I0 cos (ωt′ - π/3)
Solution
V = 2V0cos 
as voltage across inductor is more circuit behaves like an inductive circuit is current lags voltage by an amount 30o
I = I0 cos 
as voltage across inductor is more circuit behaves like an inductive circuit is current lags voltage by an amount 30o I = I0 cos Create a free account to view solution
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