ElectroMagnetic InductionMedium
Question
A 20 m long uniform copper wire held horizontally is allowed to fall under the gravity ( $g = 10\text{ }m/s^{2}$ ) through a uniform horizontal magnetic field of 0.5 Gauss perpendicular to the length of the wire. The induced EMF across the wire it travells a vertical distance of 200 m is $\_\_\_\_$ mV .
Options
A.$0.2\sqrt{10}$
B.$20\sqrt{10}$
C.$2\sqrt{10}$
D.$200\sqrt{10}$
Solution
$\varepsilon = vB\mathcal{l}$
$$\begin{matrix} v & \ = \sqrt{2gh} = \sqrt{2 \times 10 \times 200} = 20\sqrt{10} \\ \varepsilon & \ = (20\sqrt{10})\left( 0.5 \times 10^{- 4} \right)20 \\ & \ = 20\sqrt{10} \times 10^{- 3} = 20\sqrt{10}mV \end{matrix}$$
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