ElectroMagnetic InductionHard
Question
For a inductor coil L = 0.04 H then work done by source to establish a current of 5A in it is : -
Options
A.0.5 J
B.1.00 J
C.100 J
D.20 J
Solution
Work done = LI02 = (0.04) (5)2 = 1.0 J
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