Analytical ChemistryHard
Question
A white crystalline solid (A) on boiling with caustic soda solution gave a gas (B), which when passed through an alkaline solution of potassium mercuric iodide gave brown precipitate. The substance (A) on heating gave a gas (X), which rekindled a glowing splinter but did not give brown fumes with nitric oxide .The gas (B) is :
Options
A.H2S
B.NH3
C.HCl
D.CO2
Solution
The gas must be NH3, so can give brown precipitate of iodide of millon′s base with potassium mercuric iodide.
NH4NO3 is compound (A)
NH4+ + OH- → NH3↑ + H2O.
NH4+ + 2[HgI4]2- + 4OH- → HgO.Hg(NH2) I ↓ (brown) + 3H2O.
NH4NO3 → N2O + 2H2O.
N2O supports combustion.
2N2O → 2N2 + O2.
NH4NO3 is compound (A)
NH4+ + OH- → NH3↑ + H2O.
NH4+ + 2[HgI4]2- + 4OH- → HgO.Hg(NH2) I ↓ (brown) + 3H2O.
NH4NO3 → N2O + 2H2O.
N2O supports combustion.
2N2O → 2N2 + O2.
Create a free account to view solution
View Solution FreeMore Analytical Chemistry Questions
Potassium ferrocyanide is used for testing...Which of the following reagents can be used for making the distinction between AgCl and AgI ?...In the fourth group, white precipitate of Mn(OH)2 on heating with PbO2 and concentrated HNO3 gives red-violet (purple) c...A white crystalline substance dissolves in water. On passing H2S in this solution, a black precipitate is obtained. The ...Dimethyl gloxime gives a red preipitate with Ni2+, which is used for its detection. To get this precipitate reddily, the...