Analytical ChemistryHard
Question
A white crystalline solid (A) on boiling with caustic soda solution gave a gas (B), which when passed through an alkaline solution of potassium mercuric iodide gave brown precipitate. The substance (A) on heating gave a gas (X), which rekindled a glowing splinter but did not give brown fumes with nitric oxide .The gas (B) is :
Options
A.H2S
B.NH3
C.HCl
D.CO2
Solution
The gas must be NH3, so can give brown precipitate of iodide of millon′s base with potassium mercuric iodide.
NH4NO3 is compound (A)
NH4+ + OH- → NH3↑ + H2O.
NH4+ + 2[HgI4]2- + 4OH- → HgO.Hg(NH2) I ↓ (brown) + 3H2O.
NH4NO3 → N2O + 2H2O.
N2O supports combustion.
2N2O → 2N2 + O2.
NH4NO3 is compound (A)
NH4+ + OH- → NH3↑ + H2O.
NH4+ + 2[HgI4]2- + 4OH- → HgO.Hg(NH2) I ↓ (brown) + 3H2O.
NH4NO3 → N2O + 2H2O.
N2O supports combustion.
2N2O → 2N2 + O2.
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