ElectroMagnetic InductionHard
Question
A condenser of capacity 6 μF is fully charged using a 6-volt battery. The battery is removed and a resistance less 0.2 mH inductor is connected across the condenser. The current which is flowing through the inductor when one-third of the total energy is in the magnetic field of the inductor is : -
Options
A.0.1 A
B.0.2 A
C.0.4 A
D.0.6 A
Solution
Total energy = Initial energy on capacitor = 
CV2, Magnetic field energy = LI2
∴
LI2 = 
CV2 ⇒ ⇒ I = 
= 0.6 A
CV2, Magnetic field energy = LI2∴
LI2 = CV2 ⇒ ⇒ I = = 0.6 ACreate a free account to view solution
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