ElectroMagnetic InductionHard
Question
Earth′s surface is a conductor with a uniform surface charge density s. It rotates about its axis with angular velocity ω. Suppose the magnetic field due to Sun at Earth at some instant is a uniform field B pointing along earths axis. Then the emf developed between the pole and equator of earth due to this field is. (Re = radius of earth)
Options
A.1/2 BωRe2
B.BωRe2
C.3/2 BωRe2
D.0
Solution
the equator can be seen as a conducting ring of radius Re revolving with angular velocity ω in a perpendicular magnetic field B.
∴Potential difference. across its center and periphery =
Potential at pole = potential of the axis of earth i.e. potential at point O
∴ Veqvator − Vpole =
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