ElectroMagnetic InductionHard
Question
A wire frame PQRSTU is moving horizontally with velocity v in a uniform magnetic field B acting perpendicular to its plane as shown in the figure. Choose the INCORRECT statement.
Options
A.the magnitude of induced emf between P and Q is Bv 
B.the magnitude of induced emf between P and Q is Bv 
C.The electric field in the portion RS of wire is non-zero.
D.The electric field in the portion QP of wire is non-zero.
Solution
Emf induce in PQ will be BLV (L=l/3)
Electric field will be S→R in RS section
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