Rotational MotionHard
Question
A uniform circular disc placed on a rough horizontal surface has initially velocity v0 and an angular velocity ω0 as shown in the figure. The disc comes to rest after moving some distance in the direction of motion. 
Then is
Then is Options
A.1/2
B.1
C.3/2
D.2
Solution
As the disc comes to rest,
So 0 = v0 - μgt ⇒ t =
Also 0 = ω0 - αt ⇒ t =
Thus
⇒
So 0 = v0 - μgt ⇒ t =
Also 0 = ω0 - αt ⇒ t =
Thus
⇒
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