GravitationHard
Question
The dependence of acceleration due to gravity g on the distance r from the centre of the earth, assumed to be a sphere of radius R of uniform density is shown in figure below
(1)
(2)
(3)
(4)
The correct figure is
(1)
(2)
(3)
(4)
The correct figure is
Options
A.(4)
B.(1)
C.(2)
D.(3)
Solution
The acceleration due to gravity at a depath d below surface of earth is
g′ = 0 at d = R
i.e., acceleration due to gravity is zero at the centre of earth.
Thuus, the variation in value of g with r is
For r > R,
⇒ g′ ∝
Here, R + h = r
For r < R, g′ = g
Here, R - d = r ⇒ g′ ∝ r
Therefore, the variation of g with distace from centre of the earth will be as shown in the figure.

g′ = 0 at d = R
i.e., acceleration due to gravity is zero at the centre of earth.
Thuus, the variation in value of g with r is
For r > R,
⇒ g′ ∝
Here, R + h = r
For r < R, g′ = g

Here, R - d = r ⇒ g′ ∝ r
Therefore, the variation of g with distace from centre of the earth will be as shown in the figure.

Create a free account to view solution
View Solution FreeMore Gravitation Questions
The time period of an earth satellite in circular orbit is independent of...Two point objects of masses m and 4m are at rest at an infinite separation. They move towards each other under mutual gr...Given below are two statements :Statement I: A satellite is moving around earth in the orbit very close to the earth sur...Initially a satellite of 100 kg is in a circular orbit of radius $1.5R_{E}$. This satellite can be moved to a circular o...The gravitational field due to a mass distribution is E = in the x-direction. (K is a constant). Taking the gravitationa...