GravitationMedium
Question
A particle is projected from point A, that is at a distance 4R from the centre of the Earth, with speed v1 in a direction making 30o with the line joining the centre of the Earth and point A, as shown. Find the speed v1 of particle (in m/s) if particle passes grazing the surface of the earth. Consider gravitational interaction only between these two. (use 
= 6.4 × 107 m2 / s2)
= 6.4 × 107 m2 / s2)Options
A.
B.800
C.800 √2
D.None of these
Solution
Conserving angular momentum : m (v1 cos60o) 4R = mv2R ⇒ 
= 2
Conserving energy of the system : -
= - 
⇒
v22 - 
⇒ 
⇒ v1 = 
m/s
= 2Conserving energy of the system : -
= - ⇒
v22 - ⇒ ⇒ v1 = m/sCreate a free account to view solution
View Solution FreeMore Gravitation Questions
In a certain region of space, the gravitational field is given by - , where r is the distance and k is a constant. If th...A body of mass $m$ is taken from the surface of earth to a height equal to twice the radius of earth $\left( R_{e} \righ...A satellite is revolving round the earth with orbital speed v0. If it stops suddenly, the speed with which it will strik...The magnitudes of gravitational field at distance r1 and r2 from the centre of a uniform sphere of radius R and mass M a...A geostationary satellite is orbiting the earth at a height of 5R above the surface of the earth, R beingthe radius of t...