KinematicsHard
Question
The speed of projectile at its maximum height is half of its initai speed. The angle of projection is
Options
A.60o
B.15o
C.30o
D.45o
Solution
Let v be velocity of projectile at maximum height H
v = ucosθ
According to given problem, v =
∴
= cos θ ⇒ cos θ = 
⇒ θ = 60o
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