Hard
Question
A body of mass 2 kg has an intial velocity of 3 metre/sec along OE and it is subjected to a force of 4 N in a direction perpendicular to OE. The distance of body from o after 4 sec will be:-
Options
A.12 metre
B.20 metre
C.8 metre
D.48 metre
Solution
The acceleration of the body perpendicular to OE is,
a =
= 2m/s2
Displacement along OE, s1 = vt = 3 × 4 = 12 metre.
Displacement perpendicular to OE
s2 =
at2 = × 2 (4)2 = 16 metre
The resultant displacement,
s =
= 20 metre
a =
= 2m/s2Displacement along OE, s1 = vt = 3 × 4 = 12 metre.
Displacement perpendicular to OE
s2 =
at2 = × 2 (4)2 = 16 metreThe resultant displacement,
s =
= 20 metreCreate a free account to view solution
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