s-Block ElementsHard
Question
Consider the following statements ;
S1 : Among alkali metal, halides lithium iodide is the most covalent in nature.
S2 : Potassium is heavier than sodium.
S3 : The blue solution of alkali metal in liquid ammonia is stable at room temperature, where ammonia is still a liquid, in the presence of Fe.
S4 : The melting and boiling points of alkali metal halides always follow the trend : chloride > fluoride > bromide > iodide.
and arrange in the order of true/false.
S1 : Among alkali metal, halides lithium iodide is the most covalent in nature.
S2 : Potassium is heavier than sodium.
S3 : The blue solution of alkali metal in liquid ammonia is stable at room temperature, where ammonia is still a liquid, in the presence of Fe.
S4 : The melting and boiling points of alkali metal halides always follow the trend : chloride > fluoride > bromide > iodide.
and arrange in the order of true/false.
Options
A.T F F F
B.T T F F
C.T F T T
D.T T T F
Solution
S1 : Li+ being smaller have high polarising power and I- being larger have high polarisability. So it is most covelent among alkali metal halides according to Fajan′s rule.
S2 : The potassium is lighter than sodium. It is due to the fact that potassium has larger atomic volume than sodium, and increase in atomic weight does not over weigh the increase in atomic volume.
S3 : The presence of transition metals like iron and other impurities catalyses the decompositon of deep blue solution forming amide and liberating H2.
S4 : The trend is fluoride > chloride > bromide > iodide. As size of anion increases, the covalent character of the halide increases and so, the melting point decreases.
S2 : The potassium is lighter than sodium. It is due to the fact that potassium has larger atomic volume than sodium, and increase in atomic weight does not over weigh the increase in atomic volume.
S3 : The presence of transition metals like iron and other impurities catalyses the decompositon of deep blue solution forming amide and liberating H2.
S4 : The trend is fluoride > chloride > bromide > iodide. As size of anion increases, the covalent character of the halide increases and so, the melting point decreases.
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