Magnetic field due to currentHard
Question
Two charged particle A and B each of charge +e and masses 12 amu and 13 amu respectively follow a circular trajectory in chamber X after the velocity selector as shown in the figure. Both particles enter the velocity selector with speed 1.5 × 106 ms-1. A uniform magnetic field of strength 1.0 T is maintained within the chamber X and in the velocity selector.
Options
A.Electric field across the conducting plate of the velocity selector is - 106 NC-1î
B.Electric field across the conducting plate of the velocity selector is 106 NC-1î
C.The ratio 
of the radii of the circular paths for the two particles is 12/13
of the radii of the circular paths for the two particles is 12/13D.The ratio of the radii of the circular paths for the two particles is 13/12
of the radii of the circular paths for the two particles is 13/12Solution
= 0 ⇒
= vB∴ E = |1.5 × 10-6(- ĵ) × 1(-
) |= |1.5 × 10-6(- ĵ) × 1(-
)|= |1.5 × 10-6(- î)| N/C
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