Magnetic field due to currentHard
Question
The magnetic field at the center of a current carrying circular loop of radius $R$ is $16\mu\text{ }T$. The magnetic field at a distance $x = \sqrt{3}R$ on its axis from the centre is $\_\_\_\_$ $\mu T$.
Options
A.$2\sqrt{2}$
B.4
C.2
D.8
Solution
$\frac{\mu_{0}I}{2R} = 16\mu\text{ }T$
$$\frac{\mu_{0}{IR}^{2}}{2\left( x^{2} + R^{2} \right)^{3/2}} = \frac{\mu_{0}{IR}^{2}}{2 \times 8R^{3}} = 2\mu\text{ }T$$
Create a free account to view solution
View Solution FreeMore Magnetic field due to current Questions
A disc of radius r and positive charge q is rotating with angular speed ω in a uniform magnetic field B about a fix...n an electromagnetic wave in free space the root mean square value of the electric field is Erms = 6V/m. The peak value ...A long straight wire of radius a carries a steady current i. The current is uniformly distributed across its cross secti...A uniform magnetic field B0 ĵ exists in a space. A particle of mass m and charge q is projected towards negative x-...If an electron of velocity (2î + 3ĵ) is subjected to magnetic field of ⇋, then its :-(a) path will chang...