Magnetic field due to currentHard
Question
The magnetic field at the center of a current carrying circular loop of radius $R$ is $16\mu\text{ }T$. The magnetic field at a distance $x = \sqrt{3}R$ on its axis from the centre is $\_\_\_\_$ $\mu T$.
Options
A.$2\sqrt{2}$
B.4
C.2
D.8
Solution
$\frac{\mu_{0}I}{2R} = 16\mu\text{ }T$
$$\frac{\mu_{0}{IR}^{2}}{2\left( x^{2} + R^{2} \right)^{3/2}} = \frac{\mu_{0}{IR}^{2}}{2 \times 8R^{3}} = 2\mu\text{ }T$$
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