Magnetic field due to currentHard
Question
A charge particle of charge q, mass m is moving with initial velocity ′v′ as shown in figure in a uniform magnetic field - B
. Select the correct alternative / alternatives-
. Select the correct alternative / alternatives-Options
A.Velocity of particle when it comes out from magnetic field is 
= v cos30o î - v sin 30o ĵ
= v cos30o î - v sin 30o ĵB.Time for which the particle was in magnetic field is 
C.Distance traveled in magnetic field is 
D.The particle will never come out of magnetic field
Solution
t = 
Distance traveled
= PQ =
Velocity of exit = v0(cos 60î + sin 60ĵ)
Distance traveled
= PQ =
Velocity of exit = v0(cos 60î + sin 60ĵ)
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