Magnetic field due to currentMedium
Question
A mass spectrometer is a device which select particle of equal mass. An iron with electric charge q > 0 starts at rest from a source S and is accelerated through a potential difference V. It passes through a hole into a region of constant magnetic field 
perpendicular to the plane of the paper as shown in the figure. The particle is deflected by the magnetic field and emerges through the bottom hole at a distance d from the top hole. The mass of the particle is
perpendicular to the plane of the paper as shown in the figure. The particle is deflected by the magnetic field and emerges through the bottom hole at a distance d from the top hole. The mass of the particle isOptions
A.
B.
C.
D.
Solution
1/2 mv2 = qV ........(eq. 1)
r = d/2 = mv/qB (putting the value of velocity from eq. 1)
r = d/2 = mv/qB (putting the value of velocity from eq. 1)
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