Magnetic field due to currentHard
Question
If a charged particle of charge to mass ratio q/m = α is entering in a magnetic field of strength B at a speed v = (2αd)(B), then which of the following is correct?
Options
A.Angle subtended by charged particle at the centre of circular path is 2π.
B.The charge will move on a circular path and will come out from magnetic field at a distance 4d from the point of insertion
C.The time for which particle will be in the magnetic field is 
D.The charged particle will subtend an angle of 90o at the centre of circular path
Solution
R = 
= 2d
Angle subtended at the centre = π
Time to stay in magnetic field =
= 2dAngle subtended at the centre = π
Time to stay in magnetic field =
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