Momentum and CollisionHard
Question
There are two identical small holes on the opposite sides of a tank containing a liquid. The tank is open at the top. The difference in height between the two holes is h. As the liquid comes out of the two holes, the tank will experience a net horizontal force proportional to -
Options
A.√h
B.h
C.h3/2
D.h2
Solution
v1 =
and v2 = 
Let cross section area of hole is a then rate of flow
= av force v(avρ) = aρv2
∴ F1 = aρv12 and F2 = aρv22
Net force
= (F2 - F1) = aρ(v22 - v12) = aρ(2g(x + h) - 2gx)
= 2aρhgh
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