Momentum and CollisionHard

Question

A particle of mass m moving along x-axis has a potential energy U(x) = a + bx2 where a & b are postive constant. It will execute SHM with a frequency determined by the value of :

Options

A.a alone
B.a, b both
C.b and m both
D.b and m both

Solution

F = - = - 2bx
a = x      ⇒ - w2x
w =
F =

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