Momentum and CollisionHard
Question
A particle of mass 2m is connected by an inextensible string of length 1.2 m to a ring of mass m which is free to slide on a horizontal smooth rod. Initially the ring and the particle are at the same level with the string taut. Both are then released simultaneously. The distance in meters moved by the ring when the string becomes vertical is
Options
A.0
B.0.4
C.0.8
D.1.2
Solution
Let x = distance moved by ring
0 =
⇒ x = 0.8 m
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