Momentum and CollisionHard
Question
In the given diagram the sphere is released from rest. Just after collision with 5 kg block. It comes to rest. The 5 kg block comes to rest after moving a distance of 0.8 m.
Co-efficient of restitution will be :-

Co-efficient of restitution will be :-

Options
A.0.5
B.0.6
C.0.7
D.0.8
Solution
Very easy Question you can even calculate coefficient of friction easily.
Velocity of sphere when it collides with block is
μs =
since the block finally comes to rest and therefore the velocity of block just after collision with sphere is
q = vb2 - 2μgs ⇒ vb =
e =
= 0.8
μs =
since the block finally comes to rest and therefore the velocity of block just after collision with sphere is
q = vb2 - 2μgs ⇒ vb =
e =
Create a free account to view solution
View Solution FreeMore Momentum and Collision Questions
A particle of mass 2m is connected by an inextensible string of length 1.2 m to a ring of mass m which is free to slide ...The wettability of a surface by a liquid depends primarily on :-...Two vessels A and B have the same base area and contain water to the same height, but the mass of water in A is four tim...The figure shows the velocity as a a function of the time for an object with mass 10 kg being pushed along a frictionles...16 cm3 of water flows per second through a capillary tube of radius a cm and of length cm when connected to a pressure h...