Ionic EquilibriumHard
Question
Let the colour of the indicator HIn (colourless) will be visible only when its ionised form (pink) is 25% or more in a solution. Suppose HIn (pKa = 9.0) is added to a solution of pH = 9.6 predict what will happen. (Take log 2 = 0.3)
Options
A.pink colour will be visible
B.pink colour will not be visible
C.% of ionised form will be less than 25%
D.% of ionised form will be more than 25%
Solution
HIn → H+ + In-
KIn =
⇒ 
= 100.6 = 4
∴ % of [In-] in solution =
× 100 = 80%
so pink colour will be visible.
KIn =
⇒ = 100.6 = 4∴ % of [In-] in solution =
× 100 = 80%so pink colour will be visible.
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