Ionic EquilibriumHard
Question
At 25oC, the solubility product values of AgCl and AgCNS are 1.8 × 10-10 and 1.6 × 10-11 respectively. When a solution is saturated with both solids, calculate the ratio [Cl-]/[CNS-] and also [Ag+] in the solution.
Options
A.1.125, 4 × 10-6 M
B.11.25, 1.4 × 10-5 M
C.1.25, 4 × 10-5 M
D.1.25, 4 × 10-6 M
Solution
AgCI → Ag+ → + CI- AgCNS → Ag+ + CNS-
(x + y) x (x + y) y
So 
= 1.125 × 10 = 11.25
⇒
= 11.25 x = 11.25
KSP (AgCI) = [Ag+] [CI-] = (x + y) x = 1.8 × 10-10
12.25 y × 11.25 y = 1.8 × 10-10
y2 =
y2 =
y2 = 1.3 × 10-12
y = 1.14 × 10-6
x = 11.25 × 1.14 × 10-6 = 12.83 × 10-6
[Ag+] = [x + y] = 12.83 × 10-6 + 1.14 × 10-6 = 13.97 × 10-6 = 1.4 × 10-5 M
(x + y) x (x + y) y
So = 1.125 × 10 = 11.25
⇒
= 11.25 x = 11.25KSP (AgCI) = [Ag+] [CI-] = (x + y) x = 1.8 × 10-10
12.25 y × 11.25 y = 1.8 × 10-10
y2 =
y2 =
y2 = 1.3 × 10-12
y = 1.14 × 10-6
x = 11.25 × 1.14 × 10-6 = 12.83 × 10-6
[Ag+] = [x + y] = 12.83 × 10-6 + 1.14 × 10-6 = 13.97 × 10-6 = 1.4 × 10-5 M
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