Ionic EquilibriumHard
Question
The pH of a 0.1 molar solution of the acid HQ is 3. The value of the ionization constant, Ka of this acid is :-
Options
A.1 × 10 -7
B.3 × 10 -7
C.1 × 10 -3
D.1 × 10 -5
Solution
pH = -log[H+] pH = 3
[H+] = 10-pH = 10-3
For weak acid
[H+] =
[H+]2 = Ka × C
(10-3)+ = Ka × 0.1
Ka = 10-5
[H+] = 10-pH = 10-3
For weak acid
[H+] =
[H+]2 = Ka × C
(10-3)+ = Ka × 0.1
Ka = 10-5
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