Ionic EquilibriumHard
Question
If the solubility of lithium sodium hexafluorido aluminate, Li3Na3 (AlF6)2 is ′s′ mol lt-1, its solubility product is equal to :
Options
A.729 s8
B.12 s8
C.3900 s8
D.2916 s8
Solution
(a) Li3Na3(AlF6)2 → 3Li+ + 3Na+ + 2[AlF6]3-
3s 3s 2s
Ksp = (3s)3 (3s)3 (2s)2 = 2916 s8.
3s 3s 2s
Ksp = (3s)3 (3s)3 (2s)2 = 2916 s8.
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