Ionic EquilibriumHard
Question
What % of the carbon in the H2CO3 - HCO3- buffer should be in the form of HCO3- so as to have a neutral solution? (Ka = 4 × 10-7)
Options
A.20 %
B.40 %
C.60 %
D.80%
Solution
pH = pKa + log 
⇒ 7 = 7 - log 4 + log 
⇒ 
= 4
% of Carbon in the form of HCO3- =
× 100 = 
× 100 = 80 %
⇒ 7 = 7 - log 4 + log ⇒ = 4% of Carbon in the form of HCO3- =
× 100 = × 100 = 80 %Create a free account to view solution
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