Ionic EquilibriumMedium
Question
If pKb for fluoride ion at 25°C is 10.3, the ionization constant of hydrofluoric acid in water at this temperature is (log 2 = 0.3)
Options
A.2 × 10–4
B.2 × 10–3
C.2 × 10–5
D.5 × 10–11
Solution
$P^{K_{b}} = 10.3 = - \log K_{b} \Rightarrow K_{b} = 5 \times 10^{- 11}$
$\therefore K_{a(HF)} = \frac{K_{w}}{K_{b}\left( F^{-} \right)} = \frac{10^{- 14}}{5 \times 10^{- 11}} = 2 \times 10^{- 4}$
Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
Which of the following may act as buffer in aqueous solution?...What is the pH value of M H2SO4 ?...10 mL of 10-6 M HCI solution is mixed with 90 mL H2O. pH will change approximately:...Which of the following correctly explains the nature of boric acid in aqueous medium:...The pH of an aqueous solution of sodium chloride at 60o C is...