Ionic EquilibriumHard
Question
A 50 ml solution of strong acid of pH = 1 is mixed with a 50 ml solution of strong acid of pH = 2. The pH of the mixture will be nearly (log 5.5 = 0.74)
Options
A.0.74
B.1.26
C.1.76
D.1.5
Solution
[H+] = 
= 5.5 × 10-2 M.
∴ pH = 2 - 0.74 = 1.26
= 5.5 × 10-2 M.∴ pH = 2 - 0.74 = 1.26
Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
A buffer solution contains 1 mole of (NH4)2SO4 and 1 mole of NH4OH (Kb = 10-5). The pH of solution will be:...The solubility products of Mg(OH)2, Cd(OH)2, Al(OH)3 and Zn(OH)2 are 4 × 10–11, 8 × 10–6, 8.5 × 10–23 and 1.8 × 10–14, r...The products formed by complete hydrolysis of PCl3 are :-...Which statement is correct ?...What will be the resultant pH when 200 ml of an aqueous solution of HCl (pH = 2.0) is mixed with 300 ml of an aqueous so...