Rotational MotionHard

Question

A hoop of radius r and mass m rotating with an angular velocity ω0 is placed on a rough horizontal surface. The initial velocity of the centre of the hoop is zero. What will be the velocity of the centre of the hoop when it ceases to slip?

Options

A.
B.
C.
D.rω0 

Solution


                

By angular momentum conservation about point A
Li = Lf
mR2ω0 = mvR + mR2 
⇒         

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