Rotational MotionHard
Question
Portion AB of the wedge shown in figure is rough and BC is smooth. A solid cylinder rolls without slipping from A to B. The ratio of translational kinetic energy to rotational kinetic energy, when the cylinder reaches point C is
Options
A.3/4
B.5
C.7/5
D.8/3
Solution
For motion from A to B from energy considerations
or v2 = 
Now, for motion from B to C
⇒
thus remaining translational KE
KEt = mgh -
hence required ratio
or v2 = Now, for motion from B to C
⇒
thus remaining translational KE
KEt = mgh -
hence required ratio
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