Ionic EquilibriumHard
Question
Ca3(PO4)2 is insoluble in water. On adding a few drops of HCI to solid Ca3(PO4)2 in contact with water, the solid dissolves. The reason is:
Options
A.The solvent becomes more polar on adding HCI
B.Ca3(PO4)2 combines with HCI to form soluble CaCI2 and H3PO4
C.Ca(H2PO4)2 is formed, which dissolves
D.H3PO4, a weak acid is formed and the solubility product of Ca3(PO4)2 decrease
Solution
Ca3(PO4)2 + 6HCI → CaCI2 + 2H3PO4
soluble
soluble
Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
In a sautrated solution of the sparingly soluble strong electrolyte AgIO3(Molecular mass = 283) the equilibrium which se...The solubility of PbCl2 when it is 80% ionized is...Aniline behaves as a weak base. When 0.1 M, 50 ml solution of aniline was mixed with 0.1 M, 25 ml solution of HCl the pH...When 20 mL of M/20 NaOH is added to 10 mL of M/10 HCl, the resulting solution will...A 0.1 M acetic acid solution is titrated against 0.1 M-NaOH solution. What would be the difference in pH between 1/4 and...