Ionic EquilibriumHard

Question

Ca3(PO4)2 is insoluble in water. On adding a few drops of HCI to solid Ca3(PO4)2 in contact with water, the solid dissolves. The reason is:

Options

A.The solvent becomes more polar on adding HCI
B.Ca3(PO4)2 combines with HCI to form soluble CaCI2 and H3PO4
C.Ca(H2PO4)2 is formed, which dissolves
D.H3PO4, a weak acid is formed and the solubility product of Ca3(PO4)2 decrease

Solution

Ca3(PO4)2 + 6HCI → CaCI2 + 2H3PO4
                                        soluble

Create a free account to view solution

View Solution Free
Topic: Ionic Equilibrium·Practice all Ionic Equilibrium questions

More Ionic Equilibrium Questions

What is the solubility of Al(OH)3, (Ksp = 1 × 10-33) in a buffer solution pH = 4 ?...KSP if Mg(OH)2 is 1 × 10-12. 0.01M MgCI2 will show precipitation in a solution of pH greater than:...0.1mol HCl is dissolved in distilled water of volume V then at limV→∞ (pH)solution is equal to...pKa value of four acids are given below. The strongest acid is :...1.4 g of an organic compound was digested according to Kjeldahl′s method and the ammonia evolved was absorbed in 6...