Ionic EquilibriumHard
Question
Ca3(PO4)2 is insoluble in water. On adding a few drops of HCI to solid Ca3(PO4)2 in contact with water, the solid dissolves. The reason is:
Options
A.The solvent becomes more polar on adding HCI
B.Ca3(PO4)2 combines with HCI to form soluble CaCI2 and H3PO4
C.Ca(H2PO4)2 is formed, which dissolves
D.H3PO4, a weak acid is formed and the solubility product of Ca3(PO4)2 decrease
Solution
Ca3(PO4)2 + 6HCI → CaCI2 + 2H3PO4
soluble
soluble
Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
To prepare a buffer of pH 8.26 amount of (NH4)2 SO4 to be added to 500 mL of 0.01 M NH4OH solution [pKa (NH4+) = 9.26] i...The correct increasing order of solubility of the following substances in g/100 ml is PbSO4 (Ksp = 2 × 10−9), ZnS (Ksp =...Calcium lactate is a salt of weak acid and represented as Ca(Lac)2. A saturated solution of Ca(Lac)2 contains 0.125 mole...0.1mol HCl is dissolved in distilled water of volume V then at limV→∞ (pH)solution is equal to...The curve in the figure shows the variation of pH during the course of titration of a weak acid, HA with a strong base (...