Ionic EquilibriumHard
Question
A certain buffer solution contains equal concentration of X- and HX. The Kb for X- is 10-10. The pH of the buffer is:
Options
A.4
B.7
C.10
D.14
Solution
pH = - log Ka + log 
= - log 10-4 + log 
= 4
[Since Ka × Kb = 10-14 Given Kb = 10-10 ∴ Ka = 10-4]
= - log 10-4 + log = 4[Since Ka × Kb = 10-14 Given Kb = 10-10 ∴ Ka = 10-4]
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