Ionic EquilibriumHard
Question
When pure water is saturated with CaCO3 and CaC2O4, the concentration of calcium ion in the solution under equilibrium is 8 × 10-5 M. If the ratio of the solubility product of CaCO3 to that of CaC2O4 is 3, what is the solubility product of CaCO3 in pure water?
Options
A.4.80 × 10-8
B.9.60 × 10-9
C.9.60 × 10-8
D.4.80 × 10-9
Solution
CaCO3 ⇋ Ca+2 + CO3-2 CaC2O4 ⇋ Ca+2 + C2O4-2
x x y y
(x+y) x (x+y) y
= 3 ⇒ x = 3y
(x + y) = 8 × 10-5
(3y + y) = 8 × 10-5 ⇒ y = 2 × 10-5 x = 6 × 10-5
KSP (CaCO3) = [Ca+2] [CO3-2]
= 8 × 10-5 × 6 × 10-5
= 48 × 10-10
KSP (CaCO3) = 4.8 × 10-9
x x y y
(x+y) x (x+y) y
= 3 ⇒ x = 3y(x + y) = 8 × 10-5
(3y + y) = 8 × 10-5 ⇒ y = 2 × 10-5 x = 6 × 10-5
KSP (CaCO3) = [Ca+2] [CO3-2]
= 8 × 10-5 × 6 × 10-5
= 48 × 10-10
KSP (CaCO3) = 4.8 × 10-9
Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
Fear or excitement, generally cause on to breathe rapidly and it results in the decrease of CO2 concentration in blood. ...Liquid ammonia ionizes to slight extent. At −50°C, its self-ionization constant, K = [NH4+] [NH2−] = 10–30 M2. How many ...How many moles of NaOH must be removed from one litre of aqueous solution to change its pH from 12 to 11 ?...Which set is not correct for the solubility product (KSP), solubility (sg/litre) of sparingly soluble salt A3B2 (mol. wt...When 20 gm of naphthoic acid (C11H8O2) is dissolved in 50 gm of benzene (Kf = 1.72 Kg/m) a freezing point depression of ...