Ionic EquilibriumHard
Question
A buffer solution contains 1 mole of (NH4)2SO4 and 1 mole of NH4OH (Kb = 10-5). The pH of solution will be:
Options
A.5
B.9
C.5.3
D.8.7
Solution
pOH = pKb + log 
= pKb + log 
[NH4+] = 2 × mole of (NH4)2SO4 ∴ pOH = 5 + log 2 = 5.3]
or pH = 8.7
= pKb + log [NH4+] = 2 × mole of (NH4)2SO4 ∴ pOH = 5 + log 2 = 5.3]
or pH = 8.7
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