Coordination CompoundHard
Question
Crystal field stabilization energy for high spin d4 octahedral complex is
Options
A.- 1.8 ᐃo
B.- 1.6 ᐃo + P
C.- 1.2 ᐃo
D.- 0.6 ᐃo
Solution
In case of high spin complex, ᐃo is small. Thus, the energy required to pair up the fourth electron with the electrons of lower energy d-orbitals would be higher than that required to place the electrons in the higher d-orbital. Thus, pairing does not occur.
For high spin d octahedral complex,
∴ Crystal field stabilisation energy
= (- 3 × 0.4 + 1 × 0.6) ᐃo
= (- 1.2 + 0.6) ᐃo
= - 0.6 ᐃo
For high spin d octahedral complex,
∴ Crystal field stabilisation energy
= (- 3 × 0.4 + 1 × 0.6) ᐃo
= (- 1.2 + 0.6) ᐃo
= - 0.6 ᐃo
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